Question

ABC and DBC are two isosceles triangles on same base BC Show that angle ABD = angle ACD​

Answer 1

∆ABD=∆ACD

Step-by-step explanation:

In ∆ABC

AB=AC

∆ACB=∆ABC ( angles off to equal sides are equal) 1

In ∆DBC

DB=DC ( angles off to equal sides are equal) 2

Adding 1 and 2

∆ACB+∆DCB=∆ABC+∆DBC

∆ACD+∆ABD