Question

ABC and DBC are two isosceles triangles on the same base show that ABD = ACD.​

Answer 1

Answer

In △DAB and △DAC,

In △DAB and △DAC,AB = AC (Given)

In △DAB and △DAC,AB = AC (Given)BD = CD (Given)

In △DAB and △DAC,AB = AC (Given)BD = CD (Given)AD = AD (Common side)

In △DAB and △DAC,AB = AC (Given)BD = CD (Given)AD = AD (Common side)∴ △ ABD ≅ △ ACD (By SSS congruence rule)

In △DAB and △DAC,AB = AC (Given)BD = CD (Given)AD = AD (Common side)∴ △ ABD ≅ △ ACD (By SSS congruence rule)∴ ∠ABD = ∠ACD (By CPCT)