ABC and DBC are two isosceles triangles on the same base BC and vertices A and
D are on the same side of BC (See figure). If AD is extended to intersect BC at P, show
that:
(i) ABD ACD
(ii) ABP ACP
(iii) AP bisects A as well as D.
(iv) AP is the perpendicular bisector of BC.
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Answer:
if u want to prove them congruent
you have not mentioned the symbol.
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