Question

ABC and DBC are two isosceles triangles on the same base BC... show that angel ABD = angle ACD.. ​

Answer 1

Answer:

hey mate here is your answer.

sol,.

in triangle ABC we have

angle abc = angle acb (ISOSCELES triangles angle opposite to equal sides are equal)

in triangle BCD we have.

angle DBC=angle DCB. (reason as above.

it implies angle ABD=angle AcD.

doing sum of these.

Step-by-step explanation:

hope it helps.

Answer 2

Answer:

They are equal and the proof is as follows

Step-by-step explanation:

In case of /\ABC,

/ABC=/ACB ------- eq1         [isosceles triangle property that angles opposite to equal sides of a triangle are equal]

Now in case of /\DBC,

/DBC=/DCB ------- eq2        [isosceles triangle property that angles opposite to equal sides of a triangle are equal]

Adding eq1+eq2 we get

/ABC+/DBC=/ACB+/DCB

⇒/ABD=/ACD

Hope the answer helped