Question

ABC and DBC are two isosceles triangles on the same base BC . Show that ∠ ABD = ∠ ACD.​

Answer 1

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Answer 2

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Given

ABC and DBC are two isosceles triangles

So

$\angle{ABC}=\angle{ACB}..... >➀$

$\angle{DBC} = \angle DCB... > ➁$

Equation ➀ +➁

∠ ABD = ∠ ACD.

Hence proved.

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