Question

∆ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are the same on side of BC. If AD is extended to intersect BC at E show that
1)∆ABD=∆ACD
2)​∆ABE=∆ACE
3)AE bisect angle A as well as angle D
4)AE is the perpendicular bisector of BC

Answer 1

Answer:

All four are true

As Base is common