Math, asked by mpkushpatel000811, 9 months ago

ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are

on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P, show that

(i) ΔABD ΔACD

(ii) ΔABP ΔACP

(iii) AP bisects A as well as D.

(iv) AP is the perpendicular bisector of BC.​

Answers

Answered by Anonymous
6

Answer:

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