Question

ABC and DBC are two isosceles triangles on the same base BC (see the given figure). Show that ∠ ABD = ∠ ACD. ​

Answer 1

Answer:

ANSWER

Given ΔABC and ΔDBC are two isosceles triangles on the same base BC

In isosceles ΔABC

AB=AC

Then ∠ABC=∠ACB................................(1)

In isosceles ΔBDC

BD=DC

Then ∠CBD=∠BCD..................................(2)

Add (1) and (2) we get

∠ABC+∠CBD=∠ACB+∠BCD

But ΔABC and ΔDBC on same base

∴∠ABD=∠ACD

solution

Explanation:

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