Question

ABC and DBC are two isosceles triangles on the same base BC Show that angle ABD =angle ACD​

Answer 1

Explanation:

Given

AB = AC

BD = CD

Therefore,

angle abc = angle acb

angle dbc = angle dcb

Angles opposite to equal sides of a triangle are equal

Therefore,

angle abc + angle dbc = angle acb + angle dcb

Equals added to equals are equal

= angle abd = angle acd

Hope it helps!!