Question

ABC and DBC are two isosceles triangles on the same base BC .Show that angle ABD = angle ACD.

Answer 1

In ABC andDBC,
BC=BC { COMMON}
AB=DB {GIVEN: Isosceles triangle}
AC=DC{GIVEN}

Thus, it proves that ABC IS CONGRUENT TO DBC (BY SSS AXIOM)

Angle ABD= Angle ACD (CPCT)

Answer 2

Hello mate ☺

____________________________

$\bold\red{Solution:}$

AB=AC                  (Given)

It means that ∠ABC=∠ACB   (In triangle, angles opposite to equal sides are equal) .....(1)

BD=DC             (Given)

It means that ∠DBC=∠DCB    (In triangle, angles opposite to equal sides are equal)  ......(2)

Adding (1) and (2), we get

∠ABC+ ∠DBC=∠ACB+∠DCB

⇒∠ABD=∠ACD

I hope, this will help you.☺

Thank you______❤

_____________________________❤