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ABC and DBC are two Triangles on same base BC such that a n d lie on the opposite sides of BC if Ab = To a c and d b equals to DC show that it is a perpendicular bisector of BC

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Answered by sunnydey
1
since both the triangles are on same base
so, they together forms a quadrilateral.
In this quadrilateral the adjacent sides are equal. so, it is a rhombus and the diagonals of the rhombus are perpendicular to each other.

Therefore, AD BISECT'S BD
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