Question

ABC and DBC have common base BC. Prove that
A(ABC)/A(DBC) AO/DO​

Answer 1

Answer:

A(∆ABC) /A(∆DBC) =AO/DO

Step-by-step explanation:

A(∆ABC) H1

------------- =----- ------(Triangles have equal bases)

A(∆DBC) H2

A(∆ABC) AO

------------- = ------

A(∆DBC) DO

hence, A(∆ABC)/A(∆DBC)=AO/DO