ABC and DBC have common base BC. Prove that
A(ABC)/A(DBC) AO/DO
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Answer:
A(∆ABC) /A(∆DBC) =AO/DO
Step-by-step explanation:
A(∆ABC) H1
------------- =----- ------(Triangles have equal bases)
A(∆DBC) H2
A(∆ABC) AO
------------- = ------
A(∆DBC) DO
hence, A(∆ABC)/A(∆DBC)=AO/DO
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