Question

∆ABC and ∆DEC are shown below. Prove that ∆ABC congruent to ∆DEC.​

Answer 1

• EC=5cm
• BC=5cm
• <E=80°
• <B=80°

In ∆ABC and ∆DEC

$\because\begin{cases}\sf EC=BC \\ \sf m<E=m<B \\ \sf m<ECD=m<ACB(Opposite\:angles)\end{cases}$

Hence

$\\ \therefore\sf \Delta ABC\cong \Delta DEC(A-S-A)$

Answer 2

Answer:

Step-by-step explanation:

given : bc ≅ ce

  angle ABC ≅ CED

statement:                         Reason:

bc ≅ ce                               given

ABC ≅ CED                        given

AB ≅ ED                              Corresponding sides of a congruent triangle are equal