∆ABC and ∆DEF are equilateral triangles .If A ( ∆ABC) : A ( ∆DEF ) = 2 : 3 and AB = 6 ,
Find DE .
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Answer:
Consider , A(ΔABC):A(ΔDEF) = 1 :2
⇒
A(ΔDEF)
A(ΔABC)
=
2
1
⇒
DE
2
AB
2
=
2
1
⇒DE
2
=2AB
2
⇒DE
2
=2×4
2
[∴AB=4]
⇒DE=
32
⇒DE=4
2
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