Question

∆ABC and ∆PQR are congruent under the correspondence ABC RQP , then the part of∆ABC that correspond to measure P is​

Answer 1

Answer:

Step-by-step explanation:

36

In △ABC,  

BC

:  

CA

:  

AB

=3:4:5

Let the measure of sides  

BC

,  

CA

,  

AB

 of △ABC are 3x,4x and 5x (x>0) respectively.

Then, Perimeter of △ABC=3x+4x+5x=12x

Now,  

Perimeter of △PQR

Perimeter of △ABC

​  

=  

PR

AC

​  

 

⟹  

Perimeter of △PQR

12x

​  

=  

12

4x

​  

 

⟹Perimeter of △PQR=  

4

12×12

​  

 

∴ Perimeter of △PQR=36