∆ABC and ∆ PQR are similar,
=
Answers
Answer:
Ar. (△ABC) = 49cm
2
Ar. (△PQR) = 25cm
2
AB=5.6cm
For similar triangles the ratio of areas is equal to the ratio of square of its sides.
Thus,
A(△PQR)
A(△ABC)
=
PQ
2
AB
2
25
49
=
PQ
2
(5.6)
2
PQ
2
=
49
31.36×25
PQ
2
=16
PQ=4cm
Answer:
∆ABC ~ ∆PQR(Let ~ this be the Symbol Of Congruent ) And Now We Need To Find all Corresponding Angles
Now According To Question It's Said That ...
∆ABC ~ ∆PQR
When It's Given That A Triangle Is Congruent With Another Triangle Then
The Corresponding Angles And Sides Would Be also In The Form OF Given Order .
Example-
Let ...
∆EFG ~ ∆XYZ So Here EFG & XYZ Are Congruent Therefore The Corresponding Angles Would Be ..
< EFG & <XYZ ,
<FGE & < YZX
< GEF & <ZXY
Therefore This All Where The Corresponding Angles.. Now It's Corresponding Sides Are ...
EF & XY
FG & YZ
GE & ZX
Hence This All Where The Corresponding Sides And Angles ...
Now In Question It's Given That ∆ABC ~ ∆PQR ...
Therefore It's Corresponding Angles Would Be
<ABC & < PQR ,
<BCA & <QRA,
<CAB & <RPQ
Hence, This All Are The Corresponding Angles Of ∆ ABC & ∆ PQR ..
Now It's Corresponding Sides Are ...
AB & PQ ,
BC & QR,
CA & RP
Now By Theorem oF C.P.C.T Are Equal That Is Corresponding Parts Of Congruent Triangles Are Equal..
Therefore Here
AB = PQ
BC = QR
CA = RP
As This Sides Are Equal So Their Ration Would Be 1:1