Math, asked by anayaomg19, 2 months ago

ABC and XYZ are each 3-digit numbers, where A, B, C, X, Y and Z are different digits. What is the largest possible value of ABC - XYZ? ​

Answers

Answered by mveeranagendra
2

Answer:

987-123 is answers for this quetion

Answered by parineetisaxena
1

Answer:

For a three-digit number xyz, where x, y, and z are the digits of the number,

f(xyz)=5^x 2^y 3^z . If f(abc)=3*f(def), what is the value of abc-def ?

(A) 1

(B) 2

(C) 3

(D) 9

(E) 27

Step-by-step explanation:

This is how I solved.

f(abc) = 3 * f(def)

So, 5^a*2^b*3^c = 3*[5^d*2^e*3^f]

So, (5^a*2^b*3^c)/(5^d*2^e*3^f) = 3

So, 5^(a-d)*2^(b-e)*3^(c-f) = 3^1

So,5^(a-d)*2^(b-e)*3^(c-f) = 3^1*5^0*2^0

S0, a-d =0, b-e =0 and c -f =1.

So, a =d, b = e and c = f +1

So abc - def is equal to abc - abf

And since c = f + 1, differrence is 1

Answer is A

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