∆abc, angle a+angle b=65°and angle b+angle c=140°. value of angle a and angle c?
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given a+b=65 and b+c=140
and we have theorem sum of all angles of a triangle is 180°
so a+b+c=180
therefore 65+c=180. (a+b=65)
hence c=115°
now substituting c in b+c=140
we get b=25°
hence b=25 and c=115
and we have theorem sum of all angles of a triangle is 180°
so a+b+c=180
therefore 65+c=180. (a+b=65)
hence c=115°
now substituting c in b+c=140
we get b=25°
hence b=25 and c=115
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