Question

ABC : angleB = 62°, angleC = 47° and BC = 9 cm
anglePQR: angleP = 62°, angleR = 47° and QR = 9 cm​

Answer 1

Answer:

Step-by-step explanation:

Given,angle A= 62°

and ABC is equal to 54°

then, ACB= BAC+BCA+ABC= 180°

62+54+BCA=180°

so, BCA= 180°-116°=64°

now, given BO and CO are bisector of angle B and C

so in triangle OBC

54/2=27,

64/2=32

27+32+BOC= 180°

BOC=180-59=121°

angle OCB=64°

and angle OCB= 121°

hope it help you