ABC ARE INTEERNAL ANGLE OF TRIANGLE FIND TAN B+C/2
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Answer:
in ∆ ABC
A + B + c = 180°
=> B +C = 180 -A
Dividing both by 2
then
( B + C)/2 = ( 180 - A)/2
Step-by-step explanation:
see the attachment for the solution
formula used ; tan( 90 - ∅) = cot∅
Attachments:
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