Question

ABC are three points such that

AB=√50,BC=√98,AC=√288

Prove that AB+BC=AC​

Answer 1

Step-by-step explanation:

We have,

AB = √50

BC = √98

AC = √288

Now,

AB = √50

AB = √(2 × 25)

AB = 5√2

Similarly,

BC = √98

BC = √(2 × 49)

BC = 7√2

Also,

AC = √288

AC = √(2 × 144)

AC = 12√2

Now,

Let's add AB and BC

AB + BC

= 5√2 + 7√2

Taking √2 common

= √2(5 + 7)

= √2(12)

= 12√2 = AC

∴ AB + BC = AC

Hence proved.

Hope it helped and believing you understood it........All the best