Question

ABC are threeangle of triangle ifA+B=145and B+C= 100 than wht angle A= and angleB= and angle C=​

Answer 1

Answer:

A=80       B=65       C=35

A+B= 145

B+C= 100

By angle sum property of triangle,

      A+B+C= 180

as A+B=145,

     145+C= 180

     C=180-145

     C= 35

B+C=100

B+35=100             (C=35)

B=100-35

B=65

A+B=145

A+65=145           (B=65)

A=145-65

A=80

Answer 2

Given:-

∠A +∠B = 145°

∠B +∠C = 100°

.

.

as we know that,

angle sum property of ∆ :-

∠A +∠B + ∠C = 180°

145° + ∠C = 180°

∠C = 180°- 145°

∠C = 35°........................

.

.

∠B +∠C = 100° (Given)

∠B = 100° -∠C

∠B= 100° - 35°

∠B = 65°....................

.

.

∠A + ∠B = 145° (Given)

∠A = 145° - ∠B

∠A = 145° - 65°

∠A = 80°......................