Question

∆ABC asa kada ki,konB =100°, BC=6.4semi konC =50°ya trikonache antarvartuda kada


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Answer 1

Answer:

(i)Drawn BC = 6.4 cm

(ii)∠B=100

∘

and ∠C=50

∘

using the protector. Where the rays YB and XC meet, name the point as A

△ABC is thus obtained

(iii) Construct the angle bisectors of∠B and ∠C and let them meet at point O.

(iv) Through point O, draw a perpendicular to line. Let the perpendicular meet the line at point P.

(v) With O as centre and OP as radius , draw a circle inside the △ABC.

This is the required incircle.