∆ABC, BC = AB and angleB = 80° , then angleA is equal to
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in ∆ ABC
AB = BC
=> angle A = angle C ( angles opposite to equal sides are equal)
let us suppose angle A x
by angle sum property of triangles ,
=> angle A + angle B + angle C = 180°
=> x +80°+x = 180°
=> 2x = 100°
=> x = 100/2 => 50°
angle A = 50°
hope this helps
AB = BC
=> angle A = angle C ( angles opposite to equal sides are equal)
let us suppose angle A x
by angle sum property of triangles ,
=> angle A + angle B + angle C = 180°
=> x +80°+x = 180°
=> 2x = 100°
=> x = 100/2 => 50°
angle A = 50°
hope this helps
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