ABC can complete a work in 30 days by working together. A+C are twice efficient then B and A+B are thrice efficient then C find in how many days A alone complete the work?
Answers
A alone can complete work in 72 Days
Step-by-step explanation:
Let say A , B & C 1 day work are A , B & C respectively
A+C are twice efficient then B
A + C = 2B
=> 2B - C = A Eq1
A+B are thrice efficient then C
A + B = 3C Eq2
=> 3C - B = A Eq2
Eq1 + 2Eq2
=> 2B - C + 6C - 2B = A + 2A
=> 5C = 3A
=> C = 3A/5
3* Eq1 + Eq2
=> 6B - 3C + 3C - B = 3A + A
=> 5B = 4A
=> B = 4A/5
ABC can complete a work in 30 days by working together
=> 30(A + B + C) = Work
=> 30(A + 4A/5 + 3A/5) = Work
=> 6(5A + 4A + 3A) = Work
=> 72A = Work
A alone can complete work in 72 Days
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Step-by-step explanation:
see the below picture for easy method
