ABC can do the piece of work in 2 hour if B alone can do the same work in 80 hour how long will a and c to take to do it together if C alone can do the work in 60 hours how long will a to take to do it
Answers
Answer :-
A and C can do the same work in 80/39 i.e 2 2/39 hours.
A alone can do the same work in 240/113 i.e 2 14/113 hours
Explanation :-
ABC can the piece of work in 2 hours
So ABC's 1 hour work = 1/2
B alone can do the same work in 80 hours
So B's 1 hour work = 1/80
We know that
A and C 1 hour work = ABC 1 hour work - B's 1 hour work
= (1/2) - (1/80)
Taking LCM
= (40 - 1)/80
= 39/80
i.e A and C 1 hour work = 39/80
So A and C can do the same work in 80/39 i.e 2 2/39 hours.
C alone can do the same work in 60 hours
So C's 1 hours work = 1/60
We know that
A's 1 hour work = A and C 1 hour work - C's 1 hour work
= (39/80) - (1/60)
Taking LCM
= (117 - 4)/240
= 113/240
i.e A's 1 hour work = 113/240
So A alone can do the same work in 240/113 i.e 2 14/113 hours
ABC can do work in 2 hrs
⇒ ABC's 1 hr work = 1/2
A.T.Q,
Only B alone took 80 hrs to complete the work
⇒ B's 1 hr work = 1/80
A.T.Q,
(A and C)'s hr work = (ABC)'S 1 hr work - (B')s 1 hr work
______________[Put Values]
⇒ (1/2) - (1/80)
= (40 - 1)/80
= 39/80
So, (A and C)'s 1 hr work = 39/80
_____________________
Time required = 80/39
Time = 2.051
Time ≈ 2 hrs
A.T.Q,
(A)'s 1 hr work = (A and C)'s 1 hr work - (C)'s 1 hr work
_______________[Put Values]
⇒ (39/80) - (1/60)
⇒ (117 - 4)/240
⇒ 113/240
So,
(A)'s 1hr work = 113/240
________________________
Time Required = 240/113
Time = 2.12 hrs
Time ≈ 2 hrs