Math, asked by khanammeherunnessa, 11 months ago

ABC+CBA=DEDD Where A, B, C, D, E are distinct digits satisfying this addition fact, then E is?
A) 3
B) 5
C) 2
D) 4

Answers

Answered by jaival12
7

Answer:

C. 2

Step-by-step explanation:

4 5 7

+ 7 5 4

-----------------

1 2 1 1

Therefore , A = 4

B = 5

C = 7

D = 1

E = 2

Answered by Amreshbrainly
1

Answer:

Answer is C) 2

Step-by-step explanation:

  • So let us take the maximum value of each solve so:
  • Maximum number = 9

  • But A B C D and E are different digits so we need another number for adding:
  • 2nd maximum number 8

  • But in the hundred's place you cannot give the D as any other number except 1 (9 + 8 = 17)
  • So:
  • D = 1
  • =>  A B C

       +   C B A

        _______

            1 E 1  1

  • Now there is no non-decimal numbers that add up to 1 but we need 1 at 1000nds place because we made the D as 1.
  • But 11 is the only number that has 1 at all the places. So we could take any two digits to add up to 11:  like 8 + 3, 9 + 2, 7 + 4 etc...
  • So for example we have taken:
  • C = 9
  • A = 2

  • =>  2 B 9

        +   9 B 2

        _______

            1 E 1  1

  • Now there is 1 carry over to tens place and we need same digits to add up to 11 but there is no non-decimal numbers that add up to 11.

                1

  • =>  2 B 9

        +   9 B 2

         _______

            1 E 1  1

  • But, As there is a carry over, it will automatically been added so 11 - 1 = 10
  • Now we could only take 5 and add itself to 10
  • So:
  • B = 5

                1

  • =>  2 5 9

        +   9 5 2

        _______

            1 E 1  1

  • Then again a carry over of 1 to hundreds place.
  • Now by taking the values of C and A we could add up it to 11 and carry over of 1 which is 11+1 = 12

            1  1

  • =>  2 5 9

        +   9 5 2

       _______

           1 2 1  1

There You Go !!

Your answer is:

     A B C                       2 5 9

+   C B A        to         + 9 5 2

 ______                   ______

 D E D D                     1 2 1  1

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