∆ABC,D is mid point of AB,E is mid point of DB,F is mid point of BC if the area of triangle ABC is 64 then the area of ∆ABCis
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The question is not clear, what is to be calculated is not properly stated.
Area of triangle ABC
= 2 * Area of triangle ABF , as AF is the median of triangle ABC.
=> area of triangle ABF = 64/2 =32
Area of triangle ABF
= 2 * Area of triangle DBF , as FD is the median of triangle ABF
=> area of triangle DBF = 32/2=16
Area of triangle DBF =
= 2 * Area of triangle EBF , as EF is the median of triangle DBF.
=> area of triangle EBF = 8
Area of triangle ABC
= 2 * Area of triangle ABF , as AF is the median of triangle ABC.
=> area of triangle ABF = 64/2 =32
Area of triangle ABF
= 2 * Area of triangle DBF , as FD is the median of triangle ABF
=> area of triangle DBF = 32/2=16
Area of triangle DBF =
= 2 * Area of triangle EBF , as EF is the median of triangle DBF.
=> area of triangle EBF = 8
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