(abc-d²)(abc+d²)(a²b²c²+d⁴)
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Answer:
a⁴b⁴c⁴ - d⁸
Step-by-step explanation:
[(abc-d²)(abc+d²)](a²b²c²+d⁴) =
" (x+y)(x-y) = x²-y² " where x= abc, y= d²
[(abc)²- (d²)²] (a²b²c²+d⁴) =
(a²b²c²-d⁴) (a²b²c²+d⁴)=
" (x+y)(x-y) = x²-y² " where x= a²b²c², y=d⁴
(a²b²c²)² - (d⁴)² =
" a⁴b⁴c⁴ - d⁸ "
I hope you understand
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