∆ ABC~∆DEF and ar(∆ABC) =4ar(∆DEF). If BC=12 find EF
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Answer:
EF=6
Step-by-step explanation:
the triangles are similar
therefore, ratio of area of triangles is equal to square of corresponding sides.
ar(∆ABC)=4ar(∆DEF)
ar(∆ABC)/ar(∆DEF)=4/1
Ar.of ∆abc/ar.of triangle ∆def =(BC)^2/(EF)^2
4/1=12^2/(EF)^2
4/1=144/EF^2
(EF)^2=144/4
(EF)^2=36
EF=6
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