∆ABC ~ ∆DEF and <A+<B =140° then find <F
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Answered by
12
Answer:
40°
Step-by-step explanation:
since ∆ ABC~∆ DEF this ∆ ABC & ∆ DEF are equiangular
angleC= angleF= 180-(angleA+angleB)
180-140= 40
Answered by
3
Answer:
40° .
Since ∆ ABC ~ ∆ DEF this , ∆ ABC & ∆ DEF are equiangular.
Angle C = Angle F = 180° - ( Angle A + Angle B )
(180 - 140)° = 40°
Step-by-step explanation:
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