∆ABC ~ ∆DEF. If AC = 2.5 cm and DF = 7.5 cm, find ar ∆ABC : ar ∆DEF.
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Step-by-step explanation:
Given: AB=3cm, BC=2cm and CA=2.5cm and EF=4cm
Also, △ABC∼△DEF
Thus,
DE
AB
=
EF
BC
=
DF
AC
DE
3
=
4
2
=
DF
2.5
Hence, DE=6cm and DF=5cm
Perimeter of Δ DEF = DE+EF+EF
Perimeter of Δ DEF = 4+5+6
Perimeter of Δ DEF = 15 cm
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