∆ABC~∆DEF if area of ∆ABC =9cm^2 area of ∆DEF =16cm^2 and BC,=2.1cm find the length of EF.
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Ratio of areas of two similar triangle is equal to the square of ratio of their corresponding sides..... arABC/arDEF=(BC/EF)^2 9/16=(2.1/EF)^2 3/4=2.1/EF EF=(4×2.1)/3 EF=2.8cm
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36
Given...✍
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∆ABC ~ ∆DEF
Also...
Area of ∆ABC = 9 cm²
and Area of ∆ DEF = 16 cm²
We have to find the length of EF
Now...
∆ABC ~ ∆DEF
So,
Area of ∆ABC ÷ Area of ∆DEF = BC² ÷ EF²
9 ÷ 16 = (2.1)² ÷ (EF)²
√9 ÷ √16 = 2.1 ÷ EF
3 ÷ 4 = 2.1 ÷ EF
EF = [4 × 2.1] ÷ 3
EF = 2.8 cm
====================================
=========
=====
∆ABC ~ ∆DEF
Also...
Area of ∆ABC = 9 cm²
and Area of ∆ DEF = 16 cm²
We have to find the length of EF
Now...
∆ABC ~ ∆DEF
So,
Area of ∆ABC ÷ Area of ∆DEF = BC² ÷ EF²
9 ÷ 16 = (2.1)² ÷ (EF)²
√9 ÷ √16 = 2.1 ÷ EF
3 ÷ 4 = 2.1 ÷ EF
EF = [4 × 2.1] ÷ 3
EF = 2.8 cm
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