∆ ABC-∆DEF such that 2 AB=3 DE and BC=6 cm then EF=?
А. 16 cm
B- 12 cm
C 8 cm
D 4cm
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ΔABC∼∆DEF (given)
2AB=DE, BC=6cm (given)
∠E=∠B and ∠D=∠A and ∠F=∠C
2AB=DE
⇒
DE
AB
=
2
1
Therefore,
DE
AB
=
EF
BC
2
1
=
EF
6
or EF=12cm
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