∆abc ~ ∆ def such that AB = 5cm and DE = 15 cm
1) if DE = 21, then AC equals
2) the ratio of perimeters of ∆abc and ∆def is
3) if BC= 2cm, then EF equals
4) if AB + BC = 11cm, then find the value of (DE + EF) is
Answers
Answer:
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Given : ∆ABC ~ ∆ DEF
AB = 5cm and DE = 15 cm
To Find : if DF = 21, then AC equals
ratio of perimeters of ∆ABC and ∆ DEF
if BC= 2cm, then EF equals
AB + BC = 11cm, then find the value of (DE + EF) is
Solution:
∆ABC ~ ∆ DEF
AB/DE = BC/ EF = AC/DF
AB = 5cm and DE = 15 cm
BC/ EF = AC/DF = 5/15
=> BC/ EF = AC/DF =1/3
DF = 21, then AC equals
=> AC/21 = 1/3
=> AC = 7 cm
ratio of perimeters of ∆ABC and ∆ DEF = AB/DE = BC/ EF = AC/DF
= 1/3
if BC= 2cm, then EF equals
2/EF = 1/3
=> EF = 6 cm
AB + BC = 11cm
(AB + BC)/(DE + EF) = AB/DE = BC/ EF = AC/DF = 1/3
=> 11/(DE + EF) = 1/3
=> DE + EF = 33 cm
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