Question

ΔABC ~ ΔDEF such that,AB = 9.1 cm and DE = 6.5 cm. If the perimeter of ΔDEF is 25 cm, what is the perimeter of ΔABC?

Answer 1

AB = 9.1 cm  and DE = 6.5 cm 
Then the ratio of Side AB and DE = 9.1/6.5
 = 7: 5

The perimeter of triangle DEF = 25 cm 
Then the perimeter of triangle ABC = 25 x 7/5
 = 5 x 7 
 = 35 cm 

Answer 2

Answer:

The perimeter of ΔABC is 35 cm.

Step-by-step explanation:

Given : ΔABC ~ ΔDEF such that,AB = 9.1 cm and DE = 6.5 cm.

To Find : If the perimeter of ΔDEF is 25 cm, what is the perimeter of ΔABC?

Solution:

We are given that ΔABC ~ ΔDEF such that,AB = 9.1 cm and DE = 6.5 cm.

So, $\frac{\text{Perimeter of} \Delta ACB }{\text{Perimeter of} \Delta DFE} =\frac{AB}{DE}$

$\frac{\text{Perimeter of} \Delta ACB }{25} =\frac{9.1}{6.5}$

$\text{Perimeter of} \Delta ACB =\frac{9.1}{6.5} \times 25$

$\text{Perimeter of} \Delta ACB =35$

Hence the perimeter of ΔABC is 35 cm.