∆ ABC ~ ∆ DEF then Ab/De= EF/___?
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Given: ∆ABC and ∆DEF are equilateral triangles
Constrcution: Draw a perependicular from vertex A and D on AC and DF in both triangles.
In ∆ABX and ∆DEY
∠B = ∠C = 60∘ (∆ABC and ∆DEF are equilateral triangles)
∠AXB = ∠DYB (By construction)
By AA test of similarity
∆ABX ~ ∆DEY
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