∆ABC~∆DEP and A(∆ABC):A∆(DEF)=1:2 If AB=4 find DE
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if value of √2 is given than place it
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ABC~DEF
So, ar(ABC)/ar(DEF)=AB^2/DE^2
(by the theorem of area of
similar triangles is equally
propotional to the square
of two corresponding
side)
1/2 = (4)^2/DE^2
1/2 = 16 / DE^2
by cross multiplication
32 = DE^2
So, ar(ABC)/ar(DEF)=AB^2/DE^2
(by the theorem of area of
similar triangles is equally
propotional to the square
of two corresponding
side)
1/2 = (4)^2/DE^2
1/2 = 16 / DE^2
by cross multiplication
32 = DE^2
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