∆ABC ~ ∆EDF such that AB = 5cm, AC = 7cm, DF = 15cm and DE = 12cm. Find the
lengths of the remaining sides of the triangles.
please answer
Answers
Answered by
26
Answer:
lol
Step-by-step explanation:
△ ABC~△EDF
THEREFORE
AB/ED=BC/DF=AC/EF
5/12=BC/12=7/EF
5/12=7/EF
EF=7×12/5
=84/5
=16.8
NOW
BC/12=7/EF
BC=7×12 ×5/84
=420/84
=5
Answered by
4
Your Answer is 16.8cm
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