Math, asked by jArya5826, 2 months ago

ABC forms an equilateral triangle in which B is 2 km from A. A person starts walking from B in a
direction parallel to AC and stops when he reaches a point D directly east of C. He, then, reverses
direction and walks till he reaches a point E directly south of C. Then D is
(a) 3 km east and 1 km north of A
(b) 3 km east and 3 km north of A
(c) 3 km east and 1 km south of A
(d) 3 km west and 3 km north of A

Answers

Answered by 194568
0

Step-by-step explanation:

3 km east ad 1 km north of A

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