∆ABC has the vertices A(1, 4), B(−3, 4), and C(1, 1). Find the coordinates of the given point.
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Answer:
ABC is an isosceles triangle and lengths of sides AB=BC=
29
units
Now, area of the triangle =
2
1
×base×height=
2
1
×4×5=20squnits (Since, base is distance between A and C and height is the distance between B and the base AC
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