abc in a right angled triangle right angled at b. from b , perpendicular bd is drawn on ac. if ab=8cm, bc=6cm, then bd=?
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ab in right angled triangle ,right angles at the b. b perpendicular bd is drawn on AC. if ab =8cm, bc=6cm,then bd=
Step-by-step explanation:
8cm
Answered by
1
Answer:
√11 or √39
step explanations
In triangle ABC
AC^2=AB^2+BC^2
AC^2=8^2+6^2
AC^2=64+36
AC^2=100
AC=10
In triangle ABC BD perpendicular to AC
so AD=DC
AD=1/2AC
AD=5cm
In triangle ABD
AB^2=BD^2+AD^2
8^2=BD^2+5^2
64=BD^2+25
BD^2=64-25
BD=√39
OR
In triangle BCD
BC^2=BD^2+DC^2
6^2=BD^2+5^2
BD^2=36-25
BD=√11.
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