Math, asked by Ruthwik8576, 1 year ago

∆ABC in which AB=5cm, B=90° and BC=6cm. Construct

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Answered by anishkumar70
1
Draw a line segment AB of length 5cm.Taking B as point Construct an angle of measure 60o using a compass.Name the angle as angle ABX.Draw a line EF at a height of 3 cm such that it is parallel to the line segment AB. It must intersect ray BX at point C. Now join AC.Draw CD perpendicular to AB. CD is altitude of triangle ABC having height 3cm.
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