ABC is a cyclic quadrilateral whose diagonals intersect at point E. If DBC=70°, BAC is 30° find BCD. Further if AB=BC.Find ECD
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Step-by-step explanation:
As angle BAC is 30°, angles BAC and BDC will be 30° by a property which says angles in the same segment are equal. Now in triangle BDC ,70°+30°+angle BCD = 180° by angle sum prop.
Therefore ,we will get angle BCDas 80°.
Now if AB=BC ,in triangle ABC angle BAC=BCA as angles opp. to equal sides are equal. therefore we will get angle BAC =BCA=30° .
but we have angle BCD as 80° ,ECD will be BCD-BCA ,which will be ECD=80°-30° which is 50°
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