ABC is a isosceles right angled triangle whose angel A = 90° , ad perpendicular to bc and parallel line ba is drawn from d which is interset ac at e . if de=2cm then find the value of bc
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Answer:
3√2
Step-by-step explanation:
well E divides BC at midpoint here, so considering ADE is similar to CBA we get AB=AC=3 so BC => 3√2
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