Question

abc is a isosceles triangle right angle at c . find AB² ​

Answer 1

correct question : ABC is an isosceles triangle, right angled at C. Prove that AB^2 =2AC^2

ANSWER :

In △ABC,

By Pythagoras Theorem,

(AB)^2  =(AC) ^2

+(BC)  ^2  .....(1)

Since, △ABC is an isosceles triangle,

∴ AC=BC....(2)

∴ From (1) and (2),

(AB)^2  =2(AC)  ^2  

[hence proved]

Answer 2

Answer:

Given : △ABC is right angle , Also △ ABC is isosceles.

To prove : AB² ​ = 2AC² ​

Poof : Here,

          Hypotenuse =  AB

Also we know that △ABC is iscoceles

Hence,  AC = AC

Using Pythagoras theorem in △ACB

Hypotenuse²  = Height²  + Base²

AB² ​= AC² + BC²

AB² =  AC² + AC²                                            [ As AC = BC ]

AB² = 2AC²

Hence proved

Step-by-step explanation:

Given : △ABC is right angle , Also △ ABC is isosceles.

To prove : AB² ​ = 2AC² ​

Poof : Here,

          Hypotenuse =  AB

Also we know that △ABC is iscoceles

Hence,  AC = AC

Using Pythagoras theorem in △ACB

Hypotenuse²  = Height²  + Base²

AB² ​= AC² + BC²

AB² =  AC² + AC²                                            [ As AC = BC ]

AB² = 2AC²

Hence proved