Question

ABC is a isosceles triangle right angled at C. Prove that AB^2 =AC^2​

Answer 1

Step-by-step explanation:

Since,ABC is a isosceles triangle

C is 90°

AC = BC

By Pythagoras theorem,

AC^2 + BC^2 = AB^2

2 AC^2 = AB^2

...........Hope it helps you buddy