Question

ABC is a isosceles triangle right angled at C. Prove that AB square=2AC square

Answer 1

Since triangle ABC is right angled triangle at C therefore AC=BC
Now by Pythagoras Theron
AB*2= AC*2+BC*2
But AC=BC
Therefore AC*2=BC*2
AB*2=AC*2 + AC*2
AB*2= 2 AC*2

Answer 2

$\huge\purple{\mathbb{ANSWER}}$

In ∆ABC :—

AC=BC.........................①

∠ C=90°

AB² = AC² + BC²............(By Pythagoras Theorem)

From ①:—

AB² = 2AC²

Hence, Proved.