ABC is a isosceles triangle with ab=achi and ad is an altitude of the triangle. Prove that ad is also a median of the triangle
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Answer:
ABC is an isosceles triangle
AB=AC
AD is altitude
To show: AD is a median
Proof:
In triangle ADB and triangle ADC
angle ADB=angle ADC each 90
AB=AC given
AD=AD common
therefore,ADB=ADC-----RHS
BD=CD------cpct
D is midpoint of BC
so,AD is median.
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