Question

ABC is a isosceles triangle with AB=BC.If B is twice the measure of A, find the measure of all angles in the triangle

Answer 1

HELLO!!!

Here is your answer...

If AB=AC them,

∠C = ∠A----------(1)

∠B= 2∠A-------(2)

ATQ,

∠A + ∠B + ∠C = 180°

from eq 1, we get

2∠A + ∠B  = 180°------(3)

from eq 2, we get

∠B + ∠B = 180°

2∠B = 180°

∠B = 90°

By substituting the value of ∠B in eq (3) we get,

2∠A + 90° = 180°

2∠A = 180° -  90°

2∠A = 90°

∠A = 45°

from eq(1)

∠C = ∠A

∠C = 45°